(x-1)(x^2+2x+2)=1

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Solution for (x-1)(x^2+2x+2)=1 equation: 


Simplifying
(x + -1)(x2 + 2x + 2) = 1

Reorder the terms:
(-1 + x)(x2 + 2x + 2) = 1

Reorder the terms:
(-1 + x)(2 + 2x + x2) = 1

Multiply (-1 + x) * (2 + 2x + x2)
(-1(2 + 2x + x2) + x(2 + 2x + x2)) = 1
((2 * -1 + 2x * -1 + x2 * -1) + x(2 + 2x + x2)) = 1
((-2 + -2x + -1x2) + x(2 + 2x + x2)) = 1
(-2 + -2x + -1x2 + (2 * x + 2x * x + x2 * x)) = 1
(-2 + -2x + -1x2 + (2x + 2x2 + x3)) = 1

Reorder the terms:
(-2 + -2x + 2x + -1x2 + 2x2 + x3) = 1

Combine like terms: -2x + 2x = 0
(-2 + 0 + -1x2 + 2x2 + x3) = 1
(-2 + -1x2 + 2x2 + x3) = 1

Combine like terms: -1x2 + 2x2 = 1x2
(-2 + 1x2 + x3) = 1

Solving
-2 + 1x2 + x3 = 1

Solving for variable 'x'.

Reorder the terms:
-2 + -1 + 1x2 + x3 = 1 + -1

Combine like terms: -2 + -1 = -3
-3 + 1x2 + x3 = 1 + -1

Combine like terms: 1 + -1 = 0
-3 + 1x2 + x3 = 0

The solution to this equation could not be determined.

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